Ammonia , on reaction with hypochlorite anion, can form

Options

A. `NO`
B. `NH_4 Cl`
C. `N_2 H_4`
D. `HNO_2`

Explanation

To solve the question regarding the reaction of ammonia (NH₃) with the hypochlorite anion (OCl⁻), we can follow these steps:

### Step 1: Identify the Reactants
We have two reactants:
- Ammonia (NH₃)
- Hypochlorite ion (OCl⁻)

### Step 2: Write the Reaction
When ammonia reacts with the hypochlorite ion, the reaction can be represented as:
\[ \text{NH}_3 + \text{OCl}^- \rightarrow \text{N}_2\text{H}_4 + \text{Cl}^- + \text{H}_2\text{O} \]

### Step 3: Balance the Reaction
To ensure that the reaction is balanced, we need to check the number of atoms of each element on both sides of the equation:
- **Nitrogen (N)**: 2 on the product side (N₂H₄) and 1 on the reactant side (NH₃) → We need to adjust the number of NH₃.
- **Hydrogen (H)**: 6 on the product side (4 from N₂H₄ and 2 from H₂O) and 3 on the reactant side (NH₃) → Adjust accordingly.
- **Oxygen (O)**: 1 from OCl⁻ and 1 from H₂O → This is balanced.
- **Chlorine (Cl)**: 1 from OCl⁻ and 1 from Cl⁻ → This is balanced.

The balanced equation is:
\[ 2 \text{NH}_3 + \text{OCl}^- \rightarrow \text{N}_2\text{H}_4 + \text{Cl}^- + \text{H}_2\text{O} \]

### Step 4: Identify the Products
From the balanced equation, the products formed are:
- Hydrazine (N₂H₄)
- Chloride ion (Cl⁻)
- Water (H₂O)

### Step 5: Analyze the Options
Now, we compare the products with the options provided:
1. Nitric oxide (NO) - Not formed.
2. Ammonium chloride (NH₄Cl) - Not formed.
3. Hydrazine (N₂H₄) - Formed.
4. Nitrous acid (HNO₂) - Not formed.

### Conclusion
The correct answer is that ammonia reacts with hypochlorite anion to form **hydrazine (N₂H₄)**.

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