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In how many of the following reactions,...

In how many of the following reactions, one of the products is obtained as a yellow precipitate ?
`{:(Ba^(2+)+CrO_(4)^(2-),rarr,"Product"),(Hg^(2+)+Co^(2+)+SCN^(Θ),rarr,"Product"),(NH_(4)^(o+)+[PtCl_(6)]^(2-),rarr,"Product"),(Ag^(o+)+CrO_(4)^(2-),rarr,"Product"),(NH_(4)^(o+)+[Co(NO_(2))_(6)]^(3-),rarr,"Product"):}`

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To determine how many of the given reactions produce a yellow precipitate, we will analyze each reaction one by one. ### Step-by-Step Solution: 1. **Reaction 1: \( \text{Ba}^{2+} + \text{CrO}_4^{2-} \)** - Barium ions react with chromate ions to form barium chromate (\( \text{BaCrO}_4 \)). - **Observation**: Barium chromate is a yellow precipitate. - **Conclusion**: This reaction produces a yellow precipitate. 2. **Reaction 2: \( \text{Hg}^{2+} + \text{Co}^{2+} + \text{SCN}^{-} \)** - Mercuric ions react with cobalt ions and thiocyanate ions to form a complex. - **Observation**: The product is a complex that is blue in color. - **Conclusion**: This reaction does not produce a yellow precipitate. 3. **Reaction 3: \( \text{NH}_4^{+} + [\text{PtCl}_6]^{2-} \)** - Ammonium ions react with the hexachloroplatinate complex. - **Observation**: The product \( \text{NH}_4[PtCl_6] \) is a yellow precipitate. - **Conclusion**: This reaction produces a yellow precipitate. 4. **Reaction 4: \( \text{Ag}^{+} + \text{CrO}_4^{2-} \)** - Silver ions react with chromate ions to form silver chromate (\( \text{Ag}_2\text{CrO}_4 \)). - **Observation**: Silver chromate is red in color. - **Conclusion**: This reaction does not produce a yellow precipitate. 5. **Reaction 5: \( \text{NH}_4^{+} + [\text{Co(NO}_2)_6]^{3-} \)** - Ammonium ions react with the complex of cobalt and nitrite. - **Observation**: The product is a complex that is yellow in color. - **Conclusion**: This reaction produces a yellow precipitate. ### Summary of Results: - **Reactions producing yellow precipitate**: - Reaction 1: Yes (Barium chromate) - Reaction 2: No - Reaction 3: Yes (Hexachloroplatinate) - Reaction 4: No - Reaction 5: Yes (Cobalt nitrite complex) ### Final Count: - Total reactions producing yellow precipitate: **3 (Reactions 1, 3, and 5)**. ### Answer: **3** ---

To determine how many of the given reactions produce a yellow precipitate, we will analyze each reaction one by one. ### Step-by-Step Solution: 1. **Reaction 1: \( \text{Ba}^{2+} + \text{CrO}_4^{2-} \)** - Barium ions react with chromate ions to form barium chromate (\( \text{BaCrO}_4 \)). - **Observation**: Barium chromate is a yellow precipitate. - **Conclusion**: This reaction produces a yellow precipitate. ...
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