Five isomeric p-subsituted aromatic compounds (A) to (E ) with molecular formula `C_(8)H_(8)O_(2)` are given for identifyication. Based on the following observition, give the strucctures of the compounds.
i. Both (A) and (B) form a silver mirror with Tollens reagent, (B) also gives a positive test with neutral `FeCl_(3)` solution.
ii. (C ) gives positive iodoform test.
iii. (D) is readily extracted in aqueous `NaHCO_(3)` solution.
iv. (E ) on acid hydrolysis gives 1,4-dihydroxy benzene.
Compound (B) is:

Options

A.
B.
C.
D.

Explanation

To identify the structure of compound (B) among the five isomeric p-substituted aromatic compounds with the molecular formula C8H8O2, we will analyze the given observations step by step.

### Step 1: Analyze the Observations
The first observation states that both (A) and (B) form a silver mirror with Tollens' reagent. This indicates that both compounds contain an aldehyde group (–CHO) because Tollens' reagent is used to test for the presence of aldehydes.

### Step 2: Identify the Functional Groups
The second part of the observation for compound (B) mentions that it gives a positive test with neutral FeCl3 solution. This indicates the presence of a phenolic –OH group, as phenols react with FeCl3 to form colored complexes.

### Step 3: Determine the Structure of Compound (B)
Since compound (B) has both an aldehyde group and a hydroxyl group, we can deduce its structure. The molecular formula C8H8O2 suggests that the compound is likely a para-substituted aromatic compound.

- The benzene ring contributes 6 carbon atoms.
- The aldehyde group (–CHO) contributes 1 carbon atom.
- The hydroxyl group (–OH) does not contribute to the carbon count but does contribute to the overall structure.

Thus, we have:
- 6 (from benzene) + 1 (from aldehyde) + 1 (from hydroxyl) = 8 carbon atoms.

### Step 4: Visualize the Structure
Given that the aldehyde and hydroxyl groups are para to each other, the structure of compound (B) can be drawn as follows:
- A benzene ring with a –CHO group at one position and a –OH group at the para position.

The structure can be represented as:
```
OH
|
C6H4 - CHO
```
This corresponds to para-hydroxybenzaldehyde (or p-hydroxybenzaldehyde).

### Conclusion
Thus, the structure of compound (B) is para-hydroxybenzaldehyde.