Five isomeric p-subsituted aromatic compounds (A) to (E ) with molecular formula `C_(8)H_(8)O_(2)` are given for identifyication. Based on the following observition, give the strucctures of the compounds.
i. Both (A) and (B) form a silver mirror with Tollens reagent, (B) also gives a positive test with neutral `FeCl_(3)` solution.
ii. (C ) gives positive iodoform test.
iii. (D) is readily extracted in aqueous `NaHCO_(3)` solution.
iv. (E ) on acid hydrolysis gives 1,4-dihydroxy benzene.
Compound (C ) is:

Options

A.
B.
C.
D.

Explanation

To identify the structure of compound (C) from the five isomeric p-substituted aromatic compounds (A) to (E) with the molecular formula C8H8O2, we will analyze the observations provided step by step.

### Step-by-Step Solution:

1. **Understanding the Iodoform Test**:
- The iodoform test is positive for compounds that contain a methyl ketone (R-CO-CH3) or a secondary alcohol that can be oxidized to a methyl ketone. The test involves the reaction of the compound with iodine and sodium hydroxide, producing a yellow precipitate of iodoform (CHI3).
- Therefore, we need to find a compound among A to E that contains the structure of a methyl ketone or can be oxidized to one.

2. **Analyzing the Given Compounds**:
- We need to check the structures of the compounds A to E to see which one contains the methyl ketone functional group (C=O with a CH3 group attached).
- The molecular formula C8H8O2 suggests that we are dealing with aromatic compounds, and we need to look for para-substituted structures.

3. **Identifying Compound (C)**:
- From the observations, we know that compound (C) must have the structure that allows it to give a positive iodoform test.
- Upon examining the possible structures:
- (A) does not have the required methyl ketone structure.
- (B) does not have the required structure.
- (C) must contain the structure that allows for the iodoform test.
- (D) does not have the required structure.
- (E) does not have the required structure.

4. **Conclusion**:
- The only compound that meets the criteria for the iodoform test is compound (A), which has the structure of a methyl ketone (C=O with a CH3 group).
- Therefore, compound (C) is identified as compound (A).

### Final Answer:
Compound (C) is: **p-Methylacetophenone (C6H5COCH3)**.