Which of the following compounds on oxidation with `(CH_(3)COO)_(4)` Pd would give the product `OHC(CH_(2))_(4)CHO` ?

Options

A.
B.
C.
D.

Explanation

To determine which compound, when oxidized with lead tetraacetate \((CH_3COO)_4Pd\), yields the product \(OHC(CH_2)_4CHO\), we need to analyze the structure of the desired product and the requirements for the oxidation reaction.

### Step-by-Step Solution:

1. **Identify the Desired Product**:
The product is \(OHC(CH_2)_4CHO\). This indicates that we have a compound with two aldehyde groups (–CHO) and a central carbon atom that is connected to four carbon atoms (–C(CH_2)_4–).

2. **Understand the Reaction Mechanism**:
The oxidation with lead tetraacetate typically involves the cleavage of vicinal diols (1,2-diols) to form aldehydes or ketones. The reaction proceeds through a cyclic intermediate and requires syn addition, meaning that the hydroxyl groups must be added to adjacent carbons in a specific orientation.

3. **Check for Vicinal Diols**:
We need to find a compound that contains vicinal diols, as this is a prerequisite for the reaction with lead tetraacetate. The diols must be on adjacent carbon atoms.

4. **Evaluate the Options**:
- **Option A**: If this compound has vicinal diols in a syn configuration, it could potentially lead to the desired product.
- **Option B**: If this compound has trans addition of hydroxyl groups, it cannot produce the desired product.
- **Option C**: If the diols are not vicinal, it cannot yield the desired product.
- **Option D**: Similar to option B, if it has trans addition, it cannot yield the desired product.

5. **Select the Correct Compound**:
After evaluating the options, we find that **Option A** contains vicinal diols in a syn configuration, making it the correct choice. When oxidized with lead tetraacetate, it will yield the desired product \(OHC(CH_2)_4CHO\).

### Conclusion:
The correct compound that, upon oxidation with lead tetraacetate, gives the product \(OHC(CH_2)_4CHO\) is **Option A**.

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