Cyclohexanone is subjected to reduction by `NaBH_(4)`. The product formed is:

Options

A. Cyclohexane
B. Cyclohexanal
C. Cyclohexadiene
D. Cyclohexanol

Explanation

To determine the product formed when cyclohexanone is reduced by sodium borohydride (NaBH4), we can follow these steps:

### Step 1: Identify the Reactant
Cyclohexanone is a cyclic ketone with the molecular formula C6H10O. It has a carbonyl group (C=O) that is characteristic of ketones.

### Step 2: Understand the Reducing Agent
Sodium borohydride (NaBH4) is a selective reducing agent that is commonly used to reduce carbonyl compounds, including aldehydes and ketones, to their corresponding alcohols.

### Step 3: Reaction Mechanism
When cyclohexanone is treated with NaBH4, the hydride ions (H-) from the borohydride will attack the carbonyl carbon of cyclohexanone. This results in the formation of an alkoxide intermediate.

### Step 4: Protonation of the Alkoxide
The alkoxide intermediate will then be protonated (usually by water or another proton source) to form the final alcohol product.

### Step 5: Identify the Product
The reduction of cyclohexanone leads to the formation of cyclohexanol, which is a six-membered cyclic alcohol.

### Conclusion
Thus, when cyclohexanone is reduced by sodium borohydride, the product formed is cyclohexanol.

### Final Answer
The product formed is **Cyclohexanol**.

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