Which of the following reagents can help in separating a mixture of acetone and `C CI_(4)` ?

Options

A. `NaOH`
B. `NaCl`
C. `NaHSO_(3)`
D. None of the above

Explanation

To solve the question of which reagent can help in separating a mixture of acetone and carbon tetrachloride (CCl₄), we will analyze the options provided and determine their effects on the mixture.

### Step-by-Step Solution:

1. **Understanding the Components**:
- We have a mixture of acetone (CH₃COCH₃) and carbon tetrachloride (CCl₄).
- Acetone is a polar solvent, while CCl₄ is a non-polar solvent.

2. **Analyzing the Reagents**:
- **Option A: NaOH (Sodium Hydroxide)**:
- When NaOH is added to the mixture, acetone can undergo aldol condensation, leading to the formation of products like acetic anion and alcohol. However, this reaction does not produce a precipitate, and both acetone and CCl₄ remain in the solution. Thus, NaOH cannot be used for separation.

- **Option B: NaCl (Sodium Chloride)**:
- NaCl is a neutral salt and does not react with either acetone or CCl₄. Therefore, it will not affect the mixture and cannot facilitate separation.

- **Option C: NaHSO₃ (Sodium Bisulfite)**:
- When NaHSO₃ is added to the mixture, it reacts specifically with acetone to form a bisulfite adduct, which is a precipitate (CH₃C(=O)CH₃·NaHSO₃). This reaction allows for the separation of acetone from CCl₄, as the precipitate can be filtered out. The precipitate can later be regenerated back to acetone by adding a base (like NaOH).

- **Option D: None of the Above**:
- Since we have found that NaHSO₃ can effectively separate acetone from CCl₄, this option is not correct.

3. **Conclusion**:
- The reagent that can help in separating a mixture of acetone and CCl₄ is **NaHSO₃**.

### Final Answer:
The correct option is **C: NaHSO₃**.