Consider the following reactions:

Which of the following group(s) of reagents is/are used in the above conversion?

Options

A. a.`(A) implies "Acidic" KMnO_(4), (B) implies Ca(OH)_(2)`,
`(C ) implies Zn-Hg//HCl`
B. b.`(A) implies O_(3)//Ph_(3)P, (B) implies Ba(OH)_(2), (C ) implies LAH//"ether"`
C. c.`(A) implies O_(3)//H_(2)O, (B) implies Sr(OH)_(2)`,
`(C ) implies NH_(2)NH_(2)//overset(ɵ)(O)H`
D. d.`(A) implies O_(3)//Ag_(2)O, (B) implies Ba(OH)_(2), (C ) implies HI+"Red" P`

Answer

A, C, D

Explanation

A `implies` The oxidation of `(C=C)` to acids can be carried out by either of the following: (i) acidic `KMnO_(4)`, (ii) ozonolysis following by hydrolysis `(O_(3)//H_(2)O)`, (iii) ozonolysis followed by oxidation with `Ag_(2)O, H_(2)O_(2)`, peracid, or `KMnO_(4)//NaIO_(4)`
B `implies` (II) is converted to Ca, Ba, or Sr salt by reacting with their hydroxides which on dry distillation or heating gives cyclic ketone with one `C` atom less than in II.

`C implies` The

group can be converted to `(-CH_(2)-)` by either of the following:
i. Clemmensen's reduction `(Zn-Hg//HCl)`,
ii. Wolff-Kishner reduction `(NH_(2)NH_(2)+overset(ɵ)(O)H)`, or
iii. `HI+P`
So the answer are `(a)`, `(c )`, and `(d)`.