Which of the following compounds do(es) not react with `H_(2)+Pd+C`?

Options

A. a.`Me- -= -Me`
B. b.
C. c.`MeCOMe`
D. d.`Me-N_(3)`

Explanation

To determine which of the following compounds does not react with `H2 + Pd + C`, we need to analyze the nature of the compounds and the reaction conditions. The compounds in question are likely to include different types of functional groups, such as alkynes, alkenes, azides, and ketones.

### Step-by-Step Solution:

1. **Understanding the Reaction:**
- The combination of `H2`, palladium (Pd), and carbon (C) is commonly used in catalytic hydrogenation reactions. This process typically reduces multiple types of unsaturated compounds, including alkynes (triple bonds), alkenes (double bonds), and some azides.

2. **Analyzing Each Compound:**
- **Option A: Alkyne (e.g., MeC≡CMe)**
- Alkynes can be reduced to alkenes and then to alkanes. When treated with `H2 + Pd + C`, the triple bond will first convert to a double bond and then to a single bond upon further hydrogenation.
- **Conclusion:** This compound will react.

- **Option B: Alkene (e.g., MeCH=CHMe)**
- Alkenes can also be reduced to alkanes. The double bond will break, and hydrogen will be added across the double bond.
- **Conclusion:** This compound will react.

- **Option C: Azide (e.g., MeN3)**
- Azides can be reduced to amines. The nitrogen-nitrogen bonds can be broken, and hydrogen can be added to form an amine.
- **Conclusion:** This compound will react.

- **Option D: Ketone (e.g., MeC(=O)Me)**
- Ketones are generally more stable and require stronger reducing agents to convert to alcohols. The reaction with `H2 + Pd + C` is not favorable because the carbon-oxygen double bond is stable and does not easily undergo reduction without a stronger nucleophile.
- **Conclusion:** This compound will NOT react.

3. **Final Answer:**
- The compound that does not react with `H2 + Pd + C` is **Option C: Ketone (MeC(=O)Me)**.