Alkyl isocyanides `(Roverset(o+)(N)-=overset(ɵ)(C ))` are reduced to `2^(@)` amines `(R-NH-CH_(3))` with:

Options

A. a.`LAH`
B. b.`NaBH_(4)`
C. c.`HI+P`
D. d.`H_(2)+Pt`

Answer

To solve the question regarding the reduction of alkyl isocyanides to secondary amines, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of Alkyl Isocyanides**:
- Alkyl isocyanides have the general formula `R-N≡C`, where `R` is an alkyl group. The isocyanide functional group consists of a nitrogen atom triple-bonded to a carbon atom.

2. **Understand the Reduction Process**:
- Reduction is a chemical reaction that involves the gain of electrons or a decrease in oxidation state. In this case, we are looking to reduce the isocyanide to a secondary amine.

3. **Recognize the Product**:
- The product of the reduction of an alkyl isocyanide is a secondary amine, which has the general formula `R-NH-CH3` (where `R` is the alkyl group and `CH3` represents a methyl group).

4. **Identify the Reducing Agent**:
- The reduction of alkyl isocyanides to secondary amines can be achieved using hydrogen gas (H2) in the presence of a catalyst. Common catalysts for this type of reaction include platinum (Pt) or palladium (Pd).

5. **Write the Reaction**:
- The general reaction can be represented as:
\[ R-N≡C + H_2 \xrightarrow{Pt} R-NH-CH_3 \]
- Here, the alkyl isocyanide reacts with hydrogen gas in the presence of platinum to yield the corresponding secondary amine.

6. **Conclusion**:
- Therefore, the correct answer to the question is that alkyl isocyanides are reduced to secondary amines with hydrogen and platinum.

### Final Answer:
Alkyl isocyanides are reduced to secondary amines with hydrogen and platinum.

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