How many rodox equivalents are removed from two molecules of 3-PGAL ?

Options

A. 3
B. 4
C. 1
D. 2

Answer

To determine how many redox equivalents are removed from two molecules of 3-PGAL (3-phosphoglyceraldehyde), we can follow these steps:

### Step-by-Step Solution:

1. **Understanding 3-PGAL**:
- 3-PGAL is an intermediate in the glycolysis pathway and is generated from fructose 1,6-bisphosphate.

2. **Redox Reactions**:
- In the conversion of 3-PGAL to 1,3-diphosphoglycerate (1,3-BPG), a redox reaction occurs. This involves the oxidation of 3-PGAL.

3. **NAD+ Reduction**:
- During this oxidation, NAD+ (nicotinamide adenine dinucleotide) is reduced to NADH. This means that for each molecule of 3-PGAL, one redox equivalent is removed in the form of NADH.

4. **Calculating for Two Molecules**:
- Since we are considering two molecules of 3-PGAL, and each molecule contributes one redox equivalent, we multiply the number of molecules by the equivalents removed.
- Therefore, for two molecules of 3-PGAL:
\[ \text{Total redox equivalents} = 2 \text{ molecules} \times 1 \text{ redox equivalent/molecule} = 2 \text{ redox equivalents} \]

5. **Conclusion**:
- Thus, the total number of redox equivalents removed from two molecules of 3-PGAL is **2**.

### Final Answer:
The number of redox equivalents removed from two molecules of 3-PGAL is **2**.

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