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a. Would you expect the hydrides of N,O ...

a. Would you expect the hydrides of `N,O` and `F` to have lower boiling points than the hydrides of their subsequent group members? Give reason.
b. Can phosphorous with outer electronic configuration `3s^(2)3p^(3)` form `PH_(5)`?
c. How many hydrogen-bonded water molecules(s) are associated with `CuSO_(4).5H_(2)O`?

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On the basis of molecular masses of `NH_(3).H_(2)O and HF`, their boiling points are expected to be lower than those of the subsequent group member hydrides. However, due to higher electronegativity of N,O and F, the magnitude of hydrogen bonding in their hydrides will be quite appreaciable. Hence, the boiling points of `NH_(3),H_(2)O and HF` will be higher than the hydrides of their subsequent group members.
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a. Would you except the hydrides of N,O and F to have lower boiling points than the hydrides of their subsequent group members? Give reason. b. Can phosphorous with outer electronic configuration 3s^(2)3p^(3) form PH_(5) ? c. How many hydrogen-bonded water molecules(s) are associated with CuSO_(4).5H_(2)O ?

How many hydrogen-bonded water molecule(s) are associated in CuSO_(4).5H_(2)O ?

How many hydrogen-bonded water molecule(s) are associated in CuSO_(4).5H_(2)O ?

How many hydrogen-bonded water molecule(s) are associated in CuSO_(4).5H_(2)O ?

Can phosphorus with outer electronic configureation 3s^2 3p^3 " form "PH_5 ?

Assertion : Hydrides of N, O and F have lower boiling points than the hydrides of their subsequent group members. Reason : Boiling point depends upon the molecular mass only.

How many sp^(3) hybridised atoms are there in one molecule of CuSO_(4).5H_(2)O ?

Assertion : CuSO_(4).5H_(2)O has one hydrogen-bonded molecule of water. Reason : The four molecules of water are coordinated in CuSO_(4).5H_(2)O .

The number of water molecule(s) derectly bonded to the metal centre in CuSO_4.5H_2O is

The electronic configuration of given speices (X) is 1s^(2), 2s^(2)2p^(6), 3s^(2)3p^(6)3d^(5), 4s^(1) . This can be its

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