Correct regarding bond-strength is

Options

A. `C-H gt C-D gt C-T`
B. `C-H lt C-D lt C-T`
C. `C-T lt C-D = C-H`
D. `C-D gt C-H =C-T`

Answer

To determine the correct statement regarding bond strength, particularly in the context of the isotopes of hydrogen, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Isotopes of Hydrogen**:
- The isotopes of hydrogen are:
- Protium (¹H)
- Deuterium (²H or D)
- Tritium (³H or T)

2. **Understand Bond Strength**:
- Bond strength refers to the energy required to break a bond between two atoms. It can be influenced by the mass of the atoms involved in the bond.

3. **Compare the Masses of the Isotopes**:
- Protium (¹H) has the least mass.
- Deuterium (²H) has a greater mass than Protium.
- Tritium (³H) has the greatest mass among the three isotopes.

4. **Analyze the Effect of Mass on Bond Strength**:
- Generally, heavier isotopes tend to form stronger bonds due to their increased mass, which can lead to a stronger interaction with the bonding partner.

5. **Establish the Order of Bond Strength**:
- Based on the mass of the isotopes:
- The bond strength of C-T (C bonded with Tritium) is greater than C-D (C bonded with Deuterium).
- The bond strength of C-D is greater than C-H (C bonded with Protium).
- Therefore, the order of bond strength is:
- C-T > C-D > C-H

6. **Conclusion**:
- The correct statement regarding bond strength is that the bond strength increases with the mass of the hydrogen isotope involved, leading to the conclusion that C-T has the strongest bond, followed by C-D, and then C-H.

### Final Answer:
The correct statement regarding bond strength is:
**C-T (C bonded with Tritium) > C-D (C bonded with Deuterium) > C-H (C bonded with Protium)**.