Match the Following :
`{:(" Column I"," Column II"),("(A) Borax "overset(Delta)rarr.,"(p) Inorganic benzene"),("(B) Borax "+NH_(4)Cloverset(Delta)rarr,"(q) "NaBO_(2)+B_(2)O_(3)),("(C) Borax "+NH_(3)overset(Delta)rarr,"(r) "(BN)_(x)),("(D) Borax "+H_(2)Orarr,"(s) "H_(3)BO_(3)):}`

Answer

To solve the matching question, we will analyze each entry in Column I and determine the corresponding entry in Column II based on the reactions that occur when borax is heated with various substances.

### Step-by-Step Solution:

1. **Identify the Compounds in Column I:**
- (A) Borax
- (B) Borax + NH₄Cl
- (C) Borax + NH₃
- (D) Borax + H₂O

2. **Analyze Each Compound:**

**(A) Borax:**
- Borax is sodium borate, Na₂B₄O₇·10H₂O. Upon heating, it loses water and transforms into sodium metaborate and then to NaBO₂ + B₂O₃.
- **Match:** (A) → (Q) NaBO₂ + B₂O₃

**(B) Borax + NH₄Cl:**
- When borax is heated with ammonium chloride (NH₄Cl), it produces sodium chloride (NaCl), boron nitride (BN), boric anhydride (B₂O₃), and water.
- **Match:** (B) → (R) (BN)ₓ

**(C) Borax + NH₃:**
- Borax does not directly react with ammonia to form inorganic benzene (borazine). However, diborane (B₂H₆) can react with ammonia to form borazine, but this is not a direct reaction with borax.
- Since borazine is often referred to as inorganic benzene, we can tentatively match it here.
- **Match:** (C) → (P) Inorganic benzene

**(D) Borax + H₂O:**
- When borax reacts with water, it forms sodium hydroxide (NaOH) and boric acid (H₃BO₃).
- **Match:** (D) → (S) H₃BO₃

3. **Final Matches:**
- (A) → (Q)
- (B) → (R)
- (C) → (P)
- (D) → (S)

### Summary of Matches:
- (A) Borax → (Q) NaBO₂ + B₂O₃
- (B) Borax + NH₄Cl → (R) (BN)ₓ
- (C) Borax + NH₃ → (P) Inorganic benzene
- (D) Borax + H₂O → (S) H₃BO₃