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Na2CrO4 on treatment with lead acetate g...

`Na_2CrO_4` on treatment with lead acetate gives a precipitate. This dried precipitate is used as a pigment for road signs and markings . The solid is known as:

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To solve the question, we need to determine the precipitate formed when sodium chromate (Na₂CrO₄) reacts with lead acetate (Pb(CH₃COO)₂). Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the Reactants The reactants in this reaction are: - Sodium chromate (Na₂CrO₄) - Lead acetate (Pb(CH₃COO)₂) ### Step 2: Write the Reaction When sodium chromate reacts with lead acetate, a double displacement reaction occurs. The lead ions (Pb²⁺) from lead acetate will react with the chromate ions (CrO₄²⁻) from sodium chromate. The balanced chemical equation for the reaction is: \[ \text{Na}_2\text{CrO}_4 + \text{Pb(CH}_3\text{COO)}_2 \rightarrow \text{PbCrO}_4 + 2\text{NaCH}_3\text{COO} \] ### Step 3: Identify the Products From the reaction, we can see that the products formed are: - Lead chromate (PbCrO₄), which is the precipitate - Sodium acetate (NaCH₃COO) ### Step 4: Characteristics of the Precipitate Lead chromate (PbCrO₄) is known for its bright yellow color and is commonly used as a pigment in paints, road signs, and markings. ### Conclusion The solid that is formed as a precipitate from the reaction of sodium chromate with lead acetate is lead chromate (PbCrO₄). ### Final Answer The solid is known as **lead chromate (PbCrO₄)**. ---
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