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36 ml of a gaseous mixture consisting of...

36 ml of a gaseous mixture consisting of a gaseous organic compound A and just sufficient amount of oxygen required for complete combustion gives 16 ml of `CO_(2)`, 24 ml water vapour and 8 ml of `N_(2)`. The volumes are measured at same temperature and pressure.
The molecular formula of compound will be.

A

`CH_(5)N`

B

`C_(2)H_(5)N`

C

`C_(2)H_(6)N_(2)`

D

`C_(4)H_(10)N_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the molecular formula of the organic compound A from the given data, we can follow these steps: ### Step 1: Analyze the combustion reaction The combustion of a hydrocarbon (organic compound A) in the presence of oxygen (O₂) produces carbon dioxide (CO₂), water (H₂O), and nitrogen (N₂). The general reaction can be represented as: \[ \text{C}_x\text{H}_y\text{N}_z + O_2 \rightarrow CO_2 + H_2O + N_2 \] ### Step 2: Write down the volumes given From the problem, we have the following volumes: - Volume of CO₂ = 16 ml - Volume of H₂O = 24 ml - Volume of N₂ = 8 ml - Total volume of the gaseous mixture = 36 ml ### Step 3: Calculate the volume of oxygen required According to the stoichiometry of the combustion reaction: - 1 mole of CO₂ corresponds to 1 mole of carbon (C). - 1 mole of H₂O corresponds to 2 moles of hydrogen (H). - The nitrogen does not participate in the combustion but is present in the organic compound. Using the volumes, we can find the moles of each component: - Moles of CO₂ = 16 ml - Moles of H₂O = 24 ml - Moles of N₂ = 8 ml ### Step 4: Determine the moles of oxygen needed From the combustion stoichiometry: - For every 1 mole of CO₂ produced, 1 mole of O₂ is needed. - For every 1 mole of H₂O produced, 0.5 moles of O₂ is needed. Thus, the total moles of O₂ required can be calculated as: \[ \text{Moles of O}_2 = \text{Moles of CO}_2 + 0.5 \times \text{Moles of H}_2O \] Substituting the values: \[ \text{Moles of O}_2 = 16 + 0.5 \times 24 = 16 + 12 = 28 \text{ ml} \] ### Step 5: Calculate the volume of the organic compound A The volume of the organic compound A can be calculated as: \[ \text{Volume of A} = \text{Total volume} - \text{Volume of O}_2 \] Substituting the values: \[ \text{Volume of A} = 36 - 28 = 8 \text{ ml} \] ### Step 6: Determine the number of atoms (C, H, N) Now we can find the number of carbon (C), hydrogen (H), and nitrogen (N) atoms in the organic compound A: - From CO₂ (16 ml), we have 16 moles of C, which corresponds to: \[ x = \text{Moles of C} = 16 \text{ ml of CO}_2 \rightarrow x = 2 \text{ (since 8 ml of A gives 2 moles of C)} \] - From H₂O (24 ml), we have 24 moles of H, which corresponds to: \[ y = \text{Moles of H} = 2 \times \text{Moles of H}_2O = 24 \text{ ml} \rightarrow y = 6 \text{ (since 8 ml of A gives 6 moles of H)} \] - From N₂ (8 ml), we have 8 moles of N, which corresponds to: \[ z = \text{Moles of N} = 2 \times \text{Moles of N}_2 = 8 \text{ ml} \rightarrow z = 2 \text{ (since 8 ml of A gives 2 moles of N)} \] ### Step 7: Write the molecular formula Combining the values of x, y, and z, we get the molecular formula: \[ \text{Molecular formula} = \text{C}_2\text{H}_6\text{N}_2 \] ### Final Answer The molecular formula of the compound A is \( \text{C}_2\text{H}_6\text{N}_2 \). ---
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