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Given the standard electrode potentials ...

Given the standard electrode potentials ,
`K^(+)//K = - 2.93 V , Ag^(+) // Ag = 0.80 V , Hg^(2+) // Hg = 0.79 V`
`Mg^(2+)//Mg = -2.37 V. Cr^(3+)//Cr = - 0.74 V`
arrange these metals in their increasing order of the reducing power .

Text Solution

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More negative the reduction potential more easily it is oxidsed nd hence greatere is the reducing power
thus increasing oreder of reduing power will be
`Ag lt Hg lt Cr kt Mg lt K`
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