A current of 9.65A flowing for 10 minutes deposits 3.0g of the metal which is monovalent. The atomic mass of the metal is

Explanation

`SnCI_(2)rarrSn^(+2)+2CI^(-)`
`Sn^(+2)+2e^(-)rarrSn`
Mass of Sn deposited =0.238 g
m=Z it =ZQ
Charge `Q=(m)/(z)=(mxxnxxf)/(At.wt)`
`Q=(0.238)/(119)xx2xx96500`
Q=386 columb
For chrone `2CI^(-)rarrCI_(2)+2e`
Mass `m_(CI_(2))=Zit=(71)/(nF)xxQ`
`=(71)/(2xx96500)xx386=0.142 g`
To calculate weight of `SnCI_(4)` produced
`SnCI_(2)+CI_(2)rarrSnCI_(4)`
`n_(CI_(2))/(1)=n_(SnCI_(4))/(1)`
`rarr m_(SnCI_(4))/(261)=0.002`
`rarrM_(SnCI_(4))=0.522 g`
To calculate weightr of `SnCI_(2)` consumed
`SnCI_(2)+CI_(2)rarrSnCI_(4)`
`N_(SnCI_(2))/(1)=n_(CI_(2))/(1)=0.002`
`M_(SnCI_(2))=0.002xx190=0.38 g`
`m_(SnCI_(2))("remaining")=3.8-0.38-0.98=3.04 g`
`"Weight ratio" =(SnCI_(2))/(SnCI_(4))=(3.04)/(0.522)=5.829`