Home
Class 12
CHEMISTRY
Calculate the emf of the cell. Zn∣Zn^(2+...

Calculate the emf of the cell.
Zn∣`Zn^(2+)(0.001M)∣∣Cu^(2+) (0.1M)∣Cu`.The standard potential of Cu/`Cu^(2+)`half-cell is +0.34 and Zn/`Zn^(2+)` is -0.76 V.

Text Solution

AI Generated Solution

To calculate the emf of the cell given by the reaction: \[ \text{Zn} \mid \text{Zn}^{2+} (0.001 \, M) \mid \mid \text{Cu}^{2+} (0.1 \, M) \mid \text{Cu} \] we will follow these steps: ### Step 1: Write the half-reactions The half-reactions for the cell are: ...
Promotional Banner

Topper's Solved these Questions

  • COORDINATION COMPOUNDS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-G Integer Answer Type Questions )|8 Videos

  • COORDINATION COMPOUNDS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-H Multiple True-False Type Questions )|5 Videos

  • COORDINATION COMPOUNDS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-E Assertion-Reason Type Questions )|15 Videos

  • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section - J Aakash Challengers Questions)|6 Videos

  • ELECTROCHEMISTRY

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (SECTION - J) (Aakash Challengers Questions)|10 Videos

Similar Questions

Explore conceptually related problems

Calculate the emf of the given cell: Cu/ Cu^(2+)(0.01M) ∣∣ Cu^(2+) (0.001M)∣Cu is ( E^(@)Cu^(2+) /Cu=+0.34V)

Find the emf of the cell Zn(s)|Zn^(+2)(0.01 M)|KCI "saturated" |Zn^(+2)(1.0 M)|Zn(s)

Find the emf of the cell Zn(s)|Zn^(+2)(0.01 M)|KCI "saturated" |Zn^(+2)(1.0 M)|Zn(s)

Given that K_(sp) of CuS=10^(-35) and E_Cu//Cu^(2+)= (-0.34V) . The standard oxidation potential of Cu|CuS|S^(2-) Half- cell is :

Calculate the e.m.f. of the cell Zn//Zn^(2+) (0.1M) "||" Cu^(2+) (0.01M) "|"Cu E_(Zn^(2+)//Zn)^(Theta)= -0.76 " V and "E_(Cu^(2+)//Cu)^(Theta)=0.34V

The emf of the cell Zn|Zn^(2+) (1 M)||Cu^(2+)|Cu(1M) is 1.1 volt. If the standard reduction potential of Zn^(2+)|Zn is -0.78 volt, what is the standard reduction potential of Cu^(2+)|Cu

Consider the cell : Zn|Zn^(2+)(aq)(1.0M)||Cu^(2+)(aq)(1.0M)||Cu Thee standard reduction potentials are 0.350V for Cu^(2+)(aq)+2e^(-)rarrCu and -0.763V for Zn^(2+)(aq)+2e^(-) rarr Zn a. Write the cell reaction. b. Calculate the EMF of the cell. c. Is the reaction spontaneous or not ?

In the cell Zn|Zn^(2+)||Cu^(2+)|Cu , the negaitve terminal is

E^(Theta) of Cu is +0.34V while that of Zn is -0.76 V. Explain.

Calculate the standard potential of the cell ,If the standard electrode potentials of Zn^(2+)//Zn and Ag^(+) //Ag are -0.763 V and + 0.799 V respectively .