STATEMENT-1: In `[Cr(NH_(3))_(6)]Cl_(3)` , the Werner primary valency is 3 .
STATEMENT-2: `[Cr(NH_(3))_(6)]Cl_(3)` is paramagnetic .
STATEMENT-3: `[Co(NH_(3))_(6)]^(+3)` is a low spin complex

Options

A. TFT
B. TTT
C. FTT
D. TFF

Answer

To solve the problem, we need to evaluate each of the three statements provided regarding the coordination compounds. Let's analyze each statement step by step.

### Step 1: Evaluate Statement 1
**Statement 1:** In \([Cr(NH_3)_6]Cl_3\), the Werner primary valency is 3.

**Solution:**
- The compound \([Cr(NH_3)_6]Cl_3\) can be written as \([Cr(NH_3)_6]^{3+} + 3Cl^-\).
- The primary valency refers to the ionizable charge of the complex, which corresponds to the number of chloride ions that can dissociate.
- Since there are 3 chloride ions, the primary valency of chromium in this complex is indeed 3.

**Conclusion:** Statement 1 is **True (T)**.

### Step 2: Evaluate Statement 2
**Statement 2:** \([Cr(NH_3)_6]Cl_3\) is paramagnetic.

**Solution:**
- The electronic configuration of chromium (Cr) is \([Ar] 3d^5 4s^1\).
- When Cr is in the +3 oxidation state, it loses 3 electrons, resulting in the configuration \([Ar] 3d^3\).
- In an octahedral field created by the six ammonia ligands, the 3d orbitals split into two sets (t2g and eg).
- The three electrons will occupy the lower energy t2g orbitals, resulting in three unpaired electrons.
- Since there are unpaired electrons, the complex is paramagnetic.

**Conclusion:** Statement 2 is **True (T)**.

### Step 3: Evaluate Statement 3
**Statement 3:** \([Co(NH_3)_6]^{3+}\) is a low spin complex.

**Solution:**
- The electronic configuration of cobalt (Co) is \([Ar] 3d^7 4s^2\).
- For Co in the +3 oxidation state, it loses 3 electrons, resulting in the configuration \([Ar] 3d^6\).
- Ammonia (NH3) is a strong field ligand, which causes the electrons to pair up in the lower energy t2g orbitals.
- Therefore, in \([Co(NH_3)_6]^{3+}\), all six d electrons are paired, indicating that it is a low spin complex.

**Conclusion:** Statement 3 is **True (T)**.

### Final Summary
- Statement 1: True (T)
- Statement 2: True (T)
- Statement 3: True (T)

Thus, the final answer is **TTT**.