STATEMENT-1: `[M(en)Cl_(2)Br_(2)]` is optically active complex .
STATEMENT-2: en is a bidentate ligand .
STATEMENT-3: In `K[Cu(CN)_(2)]` , co-ordination number of Cu is 3 .

Options

A. TFT
B. TTT
C. TTF
D. FTT

Answer

To solve the question, we need to evaluate the three statements provided:

### Step 1: Analyze Statement 1
**Statement 1:** `[M(en)Cl₂Br₂]` is an optically active complex.

- The complex has a coordination number of 6, with one bidentate ligand (en) and two monodentate ligands (Cl and Br).
- The presence of the bidentate ligand (en) allows for the formation of two distinct optical isomers (enantiomers) that are non-superimposable mirror images of each other.
- Therefore, this statement is **True**.

### Step 2: Analyze Statement 2
**Statement 2:** en is a bidentate ligand.

- Ethylenediamine (en) has the formula `NH₂CH₂CH₂NH₂`, which contains two nitrogen atoms, each capable of donating a lone pair of electrons to the metal center.
- Since it can form two bonds with the metal, it is classified as a bidentate ligand.
- Therefore, this statement is **True**.

### Step 3: Analyze Statement 3
**Statement 3:** In `K[Cu(CN)₂]`, the coordination number of Cu is 3.

- In the complex `K[Cu(CN)₂]`, copper (Cu) is coordinated to two cyanide (CN) ligands.
- The coordination number is defined as the number of ligand donor atoms bonded to the central metal atom.
- Since there are only two CN ligands, the coordination number of Cu is 2, not 3.
- Therefore, this statement is **False**.

### Conclusion
Based on the evaluations:
- Statement 1: True
- Statement 2: True
- Statement 3: False

The correct option is **C: True, True, False**.

---