An amine reacts with `C_(6)H_(5)SO_(2)Cl` and the product is soluble in alkali, amine is

Options

A. `1^(@)` amine
B. `2^(@)` amine
C. `3^(@)` amine
D. All of these

Answer

To determine which amine reacts with benzene sulfonyl chloride (C₆H₅SO₂Cl) and produces a product that is soluble in alkali, we can analyze the reaction step by step.

### Step-by-Step Solution:

1. **Understanding the Reactants**:
- Benzene sulfonyl chloride (C₆H₅SO₂Cl) is a sulfonyl chloride that can react with amines.
- Amines can be classified into three types: primary (1°), secondary (2°), and tertiary (3°).

2. **Reaction with Primary Amine**:
- Let's consider a primary amine, such as ethylamine (C₂H₅NH₂).
- The reaction with benzene sulfonyl chloride will proceed as follows:
- The amine will attack the sulfur atom of the sulfonyl chloride, leading to the formation of a sulfonamide.
- The reaction also releases HCl as a byproduct.
- The product formed will be:
\[ C_6H_5SO_2NHC_2H_5 \]
- In this case, the product retains a hydrogen atom attached to the nitrogen (N-H bond), which is acidic.

3. **Solubility in Alkali**:
- The presence of the N-H bond in the product allows it to donate a proton (H⁺) in an alkaline solution, making it soluble in alkali.
- Therefore, the primary amine produces a product that is soluble in alkali.

4. **Reaction with Secondary Amine**:
- Now, consider a secondary amine, such as diethylamine (C₂H₅)₂NH.
- The reaction with benzene sulfonyl chloride will yield:
\[ C_6H_5SO_2N(C_2H_5)_2 \]
- Here, there is no N-H bond because both hydrogen atoms on nitrogen are replaced by ethyl groups.
- As a result, the product does not have acidic properties and is not soluble in alkali.

5. **Reaction with Tertiary Amine**:
- For a tertiary amine, such as triethylamine (N(C₂H₅)₃), the reaction with benzene sulfonyl chloride will yield:
\[ C_6H_5SO_2N(C_2H_5)_3 \]
- Similar to the secondary amine, there is no N-H bond present, meaning the product is also not acidic and is not soluble in alkali.

6. **Conclusion**:
- Only the primary amine produces a product that is soluble in alkali due to the presence of the N-H bond, which allows for proton donation.

### Final Answer:
The amine that reacts with C₆H₅SO₂Cl and produces a product soluble in alkali is a **primary amine**.