When benzene diazonium chloride is treated with cuprous chloride and HCl the product formed is

Options

A. Chlorobenzene
B. Benzene
C. Phenol
D. Chloroazobenzene

Answer

To solve the question regarding the reaction of benzene diazonium chloride with cuprous chloride (CuCl) and hydrochloric acid (HCl), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this reaction are benzene diazonium chloride (C6H5N2Cl) and cuprous chloride (CuCl) in the presence of hydrochloric acid (HCl).

2. **Recognize the Reaction Type**: This reaction is an example of the Sandmeyer reaction, which is used to synthesize aryl halides from diazonium salts.

3. **Write the Chemical Equation**:
- The benzene diazonium chloride can be represented as:
\[ C_6H_5N_2Cl \]
- When it reacts with CuCl and HCl, the nitrogen gas (N2) is liberated, and a chlorine atom (Cl) replaces the diazonium group (N2) on the benzene ring.

4. **Product Formation**:
- The product formed from this reaction is chlorobenzene (C6H5Cl). The reaction can be summarized as follows:
\[ C_6H_5N_2Cl + CuCl + HCl \rightarrow C_6H_5Cl + N_2 \uparrow + CuCl_2 \]

5. **Conclusion**: The product formed when benzene diazonium chloride is treated with cuprous chloride and HCl is chlorobenzene.

### Final Answer:
The product formed is **chlorobenzene**.

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