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During mutarotation of beta-D-glucose in...

During mutarotation of `beta`-D-glucose in aqueous solution angle of optical rotation

A

Remains constant value of + `111^(@)`

B

remains constant value of + `19.2^(@)`

C

changes from an angle of `112^(@)` to a constant value of `+52.5^(@)`

D

changes from an angle of `19.2^(@)` to a constant value of `+52.5^(@)`

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The correct Answer is:
To solve the question regarding the angle of optical rotation during the mutarotation of β-D-glucose in aqueous solution, we can follow these steps: ### Step-by-Step Solution: 1. **Understand Mutarotation**: - Mutarotation is the change in optical rotation that occurs when an α-anomer and a β-anomer of a sugar interconvert in solution. This process involves the equilibrium between the two forms. 2. **Identify the Initial Optical Rotation**: - When 100% pure β-D-glucose is dissolved in water, it has an initial specific rotation. According to the information provided, the specific rotation of β-D-glucose is approximately +18.7°. 3. **Observe the Change Over Time**: - As time progresses, the specific rotation of β-D-glucose changes due to the mutarotation process. It will eventually reach a stable value. 4. **Determine the Final Optical Rotation**: - The stable value of specific rotation for D-glucose (after mutarotation) is +52.5°. This is the equilibrium point where the mixture of α and β forms stabilizes. 5. **Conclusion**: - Therefore, during the mutarotation of β-D-glucose in aqueous solution, the angle of optical rotation changes from +18.7° to +52.5° as it reaches equilibrium. ### Final Answer: The angle of optical rotation during the mutarotation of β-D-glucose in aqueous solution changes from +18.7° to +52.5°.
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