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Value of sec^(-1)(sec.(4pi)/3) is...

Value of `sec^(-1)(sec.(4pi)/3)` is

A

`pi/3`

B

`(2pi)/3`

C

`(4pi)/3`

D

`pi/3`

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The correct Answer is:
To find the value of \( \sec^{-1}(\sec(4\pi/3)) \), we will follow these steps: ### Step 1: Understand the function The function \( \sec^{-1}(x) \) gives the angle whose secant is \( x \). The principal value of \( \sec^{-1}(x) \) lies in the range \( [0, \pi/2) \cup (\pi/2, \pi] \). ### Step 2: Set up the equation Let \( y = \sec^{-1}(\sec(4\pi/3)) \). This implies: \[ \sec(y) = \sec(4\pi/3) \] ### Step 3: Evaluate \( \sec(4\pi/3) \) To find \( \sec(4\pi/3) \), we first need to find \( \cos(4\pi/3) \): \[ \cos(4\pi/3) = \cos\left(\pi + \frac{\pi}{3}\right) = -\cos\left(\frac{\pi}{3}\right) = -\frac{1}{2} \] Thus, \[ \sec(4\pi/3) = \frac{1}{\cos(4\pi/3)} = \frac{1}{-\frac{1}{2}} = -2 \] ### Step 4: Solve for \( y \) Now we have: \[ \sec(y) = -2 \] This means: \[ y = \sec^{-1}(-2) \] ### Step 5: Find the angle corresponding to \( \sec^{-1}(-2) \) The angle \( y \) must be in the range \( [0, \pi/2) \cup (\pi/2, \pi] \). The secant function is negative in the second quadrant. The angle whose secant is \( -2 \) is: \[ y = \pi - \frac{\pi}{3} = \frac{2\pi}{3} \] ### Step 6: Conclusion Thus, the value of \( \sec^{-1}(\sec(4\pi/3)) \) is: \[ \sec^{-1}(\sec(4\pi/3)) = \frac{2\pi}{3} \] ### Final Answer: \[ \sec^{-1}(\sec(4\pi/3)) = \frac{2\pi}{3} \] ---
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AAKASH INSTITUTE ENGLISH-INVERSE TRIGONOMETRIC FUNCTIONS-ASSIGNMENT (SECTION - A)(OBJECTIVE TYPE QUESTIONS (ONE OPTION IS CORRECT))
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