Home
Class 12
MATHS
if 6sin^(-1)(x^2 -6x + 8.5)=pi then...

if `6sin^(-1)(x^2 -6x + 8.5)=pi` then

A

`x=1`

B

`x=2`

C

`x=3`

D

`x=4`

Text Solution

Verified by Experts

The correct Answer is:
B, D
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • INVERSE TRIGONOMETRIC FUNCTIONS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION - D)(LINKED COMPREHENSION TYPE QUESTIONS)|9 Videos

  • INVERSE TRIGONOMETRIC FUNCTIONS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION - E)(ASSERTION-REASON TYPE QUESTIONS)|5 Videos

  • INVERSE TRIGONOMETRIC FUNCTIONS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION - B)(OBJECTIVE TYPE QUESTIONS (ONE OPTION IS CORRECT))|36 Videos

  • INTEGRALS

    AAKASH INSTITUTE ENGLISH|Exercise Try yourself|50 Videos

  • LIMITS AND DERIVATIVES

    AAKASH INSTITUTE ENGLISH|Exercise Section - j|3 Videos

Similar Questions

Explore conceptually related problems

if 6sin_1(x^2-6x+12)=2pi , then the value of x , is

If the middle term in the binomial expansion of ((1)/(x) + x sin x )^(10) is ( 63)/( 8) , then the value of 6sin^(2) x +sin x -2 is

If tan^(-1)(x^2+3|x|-4)+cot^(-1)(4pi+sin^(-1)s in 14)=pi/2, t h e n the value of sin^(-1)2x is 6-2pi (b) 2pi-6 pi-3 (d) 3-pi

If (sin^(-1) x)^2 + (cos^(-1)x)^2 =(5pi^2)/8 then one of the values of x is

If sin ^(-1) x + sin ^(-1) y = (pi)/(6) , then cos^(-1) x + cos ^(-1) y =?

If tan^(-1)(x^2+3|x|-4)+cot^(-1)(4pi+sin^(-1)sin 14)=pi/2, t h e n the value of sin^(-1)sin2x is (a) 6-2pi (b) 2pi-6 (c) pi-3 (d) 3-pi

Solve : sin ^(-1)x - cos ^(-1) x = (pi )/(6)

Solve sin^(-1) (sin 6x) = x, x in [0,pi]

STATEMENT-1 : The solution of sin^-1 6x+sin^-1 6sqrt3x=pi/2 is , x= +- 1/12. and STATEMENT - 2 As, sin^-1 x is defined for |x| <= 1.

Consider the equation sin^(-1)(x^(2)-6x+(17)/(2))+cos^(-1)k=(pi)/(2) , then :

Home
Profile