Home
Class 12
MATHS
The number of ways to distribute m xx n...

The number of ways to distribute m `xx` n different thing among n persons equally =`((mn)!)/((m!)^(n))`
The number of ways in which 12 different books can be divided equally in 3 heaps of book is

A

`(3.12!)/((4!)^(3))`

B

`(12!)/(3!(4!)^(3))`

C

`(12!)/(3*(4!)^(3))`

D

`(3!*12!)/((4!)^(3))`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of distributing 12 different books into 3 equal heaps, we can use the formula for distributing m different things among n persons equally. The formula is given by: \[ \frac{(mn)!}{(m!)^n} \] where \( m \) is the number of items in each heap, and \( n \) is the number of heaps. ### Step 1: Determine the values of m and n In this case, we have: - Total number of books = 12 - Number of heaps (n) = 3 Since we need to divide 12 books equally into 3 heaps, each heap will contain: \[ m = \frac{12}{3} = 4 \] So, we have \( m = 4 \) and \( n = 3 \). ### Step 2: Apply the formula Now we can substitute the values of \( m \) and \( n \) into the formula: \[ \text{Number of ways} = \frac{(mn)!}{(m!)^n} = \frac{(4 \cdot 3)!}{(4!)^3} \] ### Step 3: Calculate the factorials Now, we need to calculate the factorials: - \( mn = 4 \cdot 3 = 12 \) - \( 12! = 479001600 \) - \( 4! = 24 \) - \( (4!)^3 = 24^3 = 13824 \) ### Step 4: Substitute the factorials into the formula Now we can substitute these values back into our equation: \[ \text{Number of ways} = \frac{12!}{(4!)^3} = \frac{479001600}{13824} \] ### Step 5: Perform the division Now we perform the division: \[ \frac{479001600}{13824} = 34650 \] ### Conclusion Thus, the number of ways to divide 12 different books into 3 heaps equally is: \[ \text{34650} \]
Promotional Banner

Topper's Solved these Questions

  • PERMUTATIONS AND COMBINATIONS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section E (Assertion-Reason Type Questions)|5 Videos
  • PERMUTATIONS AND COMBINATIONS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section F (Matrix-Match Type Questions)|6 Videos
  • PERMUTATIONS AND COMBINATIONS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section C Objective type questions (One option is correct )|17 Videos
  • MATRICES

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section - J) Aakash Challengers Questions|3 Videos
  • PRINCIPLE OF MATHEMATICAL

    AAKASH INSTITUTE ENGLISH|Exercise Section-D:(Assertion-Reason Type Questions)|11 Videos

Similar Questions

Explore conceptually related problems

The number of ways to distribute m xx n different thing among n persons equally = ((mn)!)/((m!)^(n)) The number of ways in which a pack of 52 card can be distributed among 4 players in a game bridge is

The number of ways to distribute m xx n different thing among n persons equally = ((mn)!)/((m!)^(n)) The numbers of ways in which a particular player holds all the aces and all of them equal number is

Number of ways in which 12 different things can be distributed in 3 groups, is

The number of ways in which 12 students can be equally divided into three groups is

In how many ways 12 different books can be distributed equally among 3 persons?

The number of ways in which 9 persons can be divided into three equal groups is

The total number of ways in which 30 mangoes can be distributed among 5 persons is

In how many ways 12 different books can be distributed equally distributed equally among 4 persons?

STATEMENT -1: The number of ways in which six different objects can be divided equally into 2 sets is 10. STATEMENT -2 , The number of ways in which six different objects be distributed equally among two persons is 20.

In how many ways can 12 books be divided in 3 students equally?