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Find the equation of line through the or...

Find the equation of line through the origin and a point where line `(x-1)/2=(y-2)/4=(z-3)/4`. Cuts
the z-axis.

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To find the equation of the line through the origin and the point where the given line intersects the z-axis, we can follow these steps: ### Step 1: Determine the point of intersection with the z-axis The given line is represented by the equation: \[ \frac{x - 1}{2} = \frac{y - 2}{4} = \frac{z - 3}{4} \] A point on the z-axis has coordinates of the form (0, 0, z). To find the point where the given line intersects the z-axis, we set \(x = 0\) and \(y = 0\). ### Step 2: Substitute x and y into the equation Substituting \(x = 0\) and \(y = 0\) into the equation: \[ \frac{0 - 1}{2} = \frac{0 - 2}{4} = \frac{z - 3}{4} \] This gives us: \[ \frac{-1}{2} = \frac{-2}{4} = \frac{z - 3}{4} \] ### Step 3: Simplify the equations From \(\frac{-1}{2} = \frac{-2}{4}\), we can see that both sides are equal, so we can now focus on finding \(z\): \[ \frac{-1}{2} = \frac{z - 3}{4} \] ### Step 4: Cross-multiply to solve for z Cross-multiplying gives: \[ -1 \cdot 4 = -2 \cdot (z - 3) \] This simplifies to: \[ -4 = -2z + 6 \] ### Step 5: Rearrange the equation to solve for z Rearranging the equation: \[ -2z = -4 - 6 \] \[ -2z = -10 \] \[ z = 5 \] ### Step 6: Identify the point of intersection Thus, the point of intersection \(P\) on the z-axis is: \[ P(0, 0, 5) \] ### Step 7: Find the direction vector of the line OP The line passes through the origin \(O(0, 0, 0)\) and the point \(P(0, 0, 5)\). The direction vector \(\vec{OP}\) is: \[ \vec{OP} = P - O = (0 - 0, 0 - 0, 5 - 0) = (0, 0, 5) \] ### Step 8: Write the equation of the line The equation of the line in symmetric form is given by: \[ \frac{x - 0}{0} = \frac{y - 0}{0} = \frac{z - 0}{5} \] This can be simplified to: \[ \frac{x}{0} = \frac{y}{0} = \frac{z}{5} \] ### Final Equation of the Line Thus, the required equation of the line through the origin and the point where the given line intersects the z-axis is: \[ x = 0, \quad y = 0, \quad z = 5t \quad (t \in \mathbb{R}) \]
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