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Find the angle between the line vecr=hat...

Find the angle between the line `vecr=hati+2hatj-hatk+lamda(hati-hatj+hatk)` and the plane `vecr*(2hati-hatj+hatk)=4`.

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The correct Answer is:
`sin ^(-1)(4/(3sqrt(2)))`
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Find the angle between the line vecr=(hati+2hatj-hatk)+lamda(hati-hatj+hatk) and the plane ver.(2hati-hatj+hatk)=4

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The angle between the line vecr=(hati+2hatj+3hatk)+lamda(2hati+3hatj+4hatk) and the plane vecr.(hati+2hatj-2hatk)=3 is (A) 0^0 (B) 60^0 (C) 30^0 (D) 90^0

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Find the shortest distance between the lines vecr=(hati+2hatj+hatk)+lamda(2hati+hatj+2hatk) and vecr=2hati-hatj-hatk+mu(2hati+hatj+2hatk) .

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