Foot of perpendicular drawn from a point P(-2, 3, 5)
on the YZ-plane is

Options

A. (1, 3, 5)
B. (-2, 3, 0)
C. (0, 3, 5)
D. (0, 3, 0)

Answer

To find the foot of the perpendicular drawn from the point \( P(-2, 3, 5) \) onto the YZ-plane, we can follow these steps:

### Step 1: Understand the YZ-plane
The YZ-plane is defined by the equation \( x = 0 \). This means that any point on the YZ-plane will have its x-coordinate equal to 0.

### Step 2: Identify the coordinates of point P
The coordinates of the point \( P \) are given as \( (-2, 3, 5) \). Here, the x-coordinate is -2, the y-coordinate is 3, and the z-coordinate is 5.

### Step 3: Set the x-coordinate to 0
Since we are projecting the point onto the YZ-plane, we need to change the x-coordinate of point P to 0. Therefore, the new coordinates will be:
- x-coordinate: 0
- y-coordinate: remains the same (3)
- z-coordinate: remains the same (5)

### Step 4: Write the coordinates of the foot of the perpendicular
Thus, the coordinates of the foot of the perpendicular from point P onto the YZ-plane will be:
\[ (0, 3, 5) \]

### Conclusion
The foot of the perpendicular drawn from the point \( P(-2, 3, 5) \) on the YZ-plane is \( (0, 3, 5) \).

---