What is the perpendicular distance of the point
(6, 7, 5) from YZ-plane?

Options

A. 8 units
B. 6 units
C. 7 units
D. 21 units

Answer

To find the perpendicular distance of the point (6, 7, 5) from the YZ-plane, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the YZ-plane**: The YZ-plane is defined by the equation x = 0. This means that any point on the YZ-plane has an x-coordinate of 0.

2. **Identify the coordinates of the point**: The given point is P(6, 7, 5). Here, the x-coordinate is 6.

3. **Determine the formula for the distance**: The perpendicular distance from a point to the YZ-plane is simply the absolute value of the x-coordinate of that point. This is because the distance is measured along the x-axis.

4. **Calculate the distance**:
\[ \text{Distance} = |x| = |6| = 6 \text{ units} \]

5. **Conclusion**: The perpendicular distance of the point (6, 7, 5) from the YZ-plane is 6 units.

### Final Answer:
The perpendicular distance from the point (6, 7, 5) to the YZ-plane is **6 units**.

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