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The points (5, -4, 2), (4, -3, 1), (7, -...

The points (5, -4, 2), (4, -3, 1), (7, -6, 4) and
(8, -7, 5) are the vertices of a

A

Parallelogram

B

Rectangle

C

Square

D

Rhombus

Text Solution

AI Generated Solution

The correct Answer is:
To determine what the points (5, -4, 2), (4, -3, 1), (7, -6, 4), and (8, -7, 5) represent in three-dimensional space, we can follow these steps: ### Step 1: Assign the Points Let: - Point A = (5, -4, 2) - Point B = (4, -3, 1) - Point C = (7, -6, 4) - Point D = (8, -7, 5) ### Step 2: Calculate the Length of AB Using the distance formula in 3D: \[ AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2} \] \[ AB = \sqrt{(4 - 5)^2 + (-3 + 4)^2 + (1 - 2)^2} \] \[ = \sqrt{(-1)^2 + (1)^2 + (-1)^2} \] \[ = \sqrt{1 + 1 + 1} = \sqrt{3} \] ### Step 3: Calculate the Length of BC \[ BC = \sqrt{(7 - 4)^2 + (-6 + 3)^2 + (4 - 1)^2} \] \[ = \sqrt{(3)^2 + (-3)^2 + (3)^2} \] \[ = \sqrt{9 + 9 + 9} = \sqrt{27} \] ### Step 4: Calculate the Length of CD \[ CD = \sqrt{(8 - 7)^2 + (-7 + 6)^2 + (5 - 4)^2} \] \[ = \sqrt{(1)^2 + (-1)^2 + (1)^2} \] \[ = \sqrt{1 + 1 + 1} = \sqrt{3} \] ### Step 5: Calculate the Length of DA \[ DA = \sqrt{(5 - 8)^2 + (-4 + 7)^2 + (2 - 5)^2} \] \[ = \sqrt{(-3)^2 + (3)^2 + (-3)^2} \] \[ = \sqrt{9 + 9 + 9} = \sqrt{27} \] ### Step 6: Calculate the Length of the Diagonal AC \[ AC = \sqrt{(7 - 5)^2 + (-6 + 4)^2 + (4 - 2)^2} \] \[ = \sqrt{(2)^2 + (-2)^2 + (2)^2} \] \[ = \sqrt{4 + 4 + 4} = \sqrt{12} \] ### Step 7: Calculate the Length of the Diagonal BD \[ BD = \sqrt{(8 - 4)^2 + (-7 + 3)^2 + (5 - 1)^2} \] \[ = \sqrt{(4)^2 + (-4)^2 + (4)^2} \] \[ = \sqrt{16 + 16 + 16} = \sqrt{48} \] ### Step 8: Analyze the Lengths From our calculations: - Length of AB = Length of CD = \( \sqrt{3} \) - Length of AD = Length of BC = \( \sqrt{27} \) - Length of AC = \( \sqrt{12} \) - Length of BD = \( \sqrt{48} \) Since opposite sides are equal (AB = CD and AD = BC) but the diagonals are not equal (AC ≠ BD), the figure formed by these points is a parallelogram. ### Conclusion The points (5, -4, 2), (4, -3, 1), (7, -6, 4), and (8, -7, 5) represent the vertices of a parallelogram in three-dimensional space. ---
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AAKASH INSTITUTE ENGLISH-THREE DIMENSIONAL GEOMETRY -ASSIGNMENT SECTION - A
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  2. The ratio in which the join of A(1, 2, 3) and B(3, 4, 6) is divided by...

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  3. The points (5, -4, 2), (4, -3, 1), (7, -6, 4) and (8, -7, 5) are the...

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  4. A line is parallel to YZ-plane, if all the points on the line have e...

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  5. The equation of a plane parallel to x-axis is

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  6. The plane uniquely determined by x-axis and y-axis is known as

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  7. The Three coordiantes planes divide the space into ……. Parts.

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  8. The intersection of XY-plane and YZ-plane is known as

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  9. It the mid-points of the sides of triangle are (1, 2, -3), (3, 0, 1)...

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  10. The shortest distance of the point (a, b, c) from y-axis is

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  11. Values of a for which the distance between the points (3, -5, 4) and...

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  12. The graph of the equation x^2+y^2=0 in the three dimensional space is ...

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  13. The coordinates of the point equidistant from the points A(0, 0, 0), ...

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  14. The plane-XY divides the join of (1, -1, 5) and (2, 3, 4) in the rat...

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  15. A parallelopiped is formed by planes drawn through the points (1, 2, ...

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  16. Find the angle between the lines 2x=3y=-z and 6x=-y=-4z.

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  17. A line makes the same angle theta with X-axis and Z-axis. If the angle...

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  18. Distance between two parallel planes 2x+y+2z=8 and 4x+2y+4z+5=0 is

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  19. The direction cosines of the normal to the plane x + 2y - 3z + 4 = 0...

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  20. Find the distance of the point (1,-2,3) from the plane x-y+z=5 measure...

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