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Values of a for which the distance betwe...

Values of a for which the distance between the
points (3, -5, 4) and (a, -8, 4) is 5 is

A

`-1 or 7`

B

`2 or 7`

C

`3 or 1`

D

`2 or 1`

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The correct Answer is:
To find the values of \( a \) for which the distance between the points \( (3, -5, 4) \) and \( (a, -8, 4) \) is 5, we can use the distance formula in three-dimensional geometry. ### Step-by-Step Solution: 1. **Identify the Points**: - Let \( P = (3, -5, 4) \) and \( Q = (a, -8, 4) \). 2. **Use the Distance Formula**: The distance \( d \) between two points \( P(x_1, y_1, z_1) \) and \( Q(x_2, y_2, z_2) \) is given by: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2} \] In our case, we have: - \( x_1 = 3 \), \( y_1 = -5 \), \( z_1 = 4 \) - \( x_2 = a \), \( y_2 = -8 \), \( z_2 = 4 \) 3. **Set Up the Equation**: We know the distance \( d = 5 \), so we can write: \[ 5 = \sqrt{(a - 3)^2 + (-8 + 5)^2 + (4 - 4)^2} \] 4. **Simplify the Equation**: Simplifying the terms inside the square root: \[ 5 = \sqrt{(a - 3)^2 + (-3)^2 + 0^2} \] This simplifies to: \[ 5 = \sqrt{(a - 3)^2 + 9} \] 5. **Square Both Sides**: To eliminate the square root, we square both sides: \[ 25 = (a - 3)^2 + 9 \] 6. **Isolate the Squared Term**: Rearranging gives: \[ (a - 3)^2 = 25 - 9 \] \[ (a - 3)^2 = 16 \] 7. **Take the Square Root**: Taking the square root of both sides gives: \[ a - 3 = \pm 4 \] 8. **Solve for \( a \)**: This results in two equations: - \( a - 3 = 4 \) which gives \( a = 7 \) - \( a - 3 = -4 \) which gives \( a = -1 \) 9. **Final Values**: Therefore, the values of \( a \) for which the distance is 5 are: \[ a = 7 \quad \text{and} \quad a = -1 \]
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AAKASH INSTITUTE ENGLISH-THREE DIMENSIONAL GEOMETRY -ASSIGNMENT SECTION - A
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