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Lines vecr = veca(1) + lambda vecb and v...

Lines `vecr = veca_(1) + lambda vecb and vecr = veca_(2) + svecb_` will lie in a Plane if

A

`veca_(1) xxveca_(2)=0`

B

`(veca_(2)-veca_(1))xxvecb_(1) xx vecb_(2) = 0`

C

`(veca_(2)-veca_(1))cdot (vecb_(1) xx vecb_(2)) = 0`

D

`vecb_(1) xxvecb_(2)=0`

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The correct Answer is:
To determine whether the lines given by the equations \(\vec{r} = \vec{a_1} + \lambda \vec{b_1}\) and \(\vec{r} = \vec{a_2} + s \vec{b_2}\) lie in a plane, we can use the following conditions: ### Step 1: Understand the Conditions for Lines to Lie in a Plane Two lines will lie in the same plane if either: 1. They intersect (the shortest distance between them is zero). 2. They are parallel (the direction ratios are proportional). ### Step 2: Condition for Intersection For the lines to intersect, the shortest distance \(d\) between them must be zero. The formula for the shortest distance between two skew lines is given by: \[ d = \frac{(\vec{a_2} - \vec{a_1}) \cdot (\vec{b_1} \times \vec{b_2})}{|\vec{b_1} \times \vec{b_2}|} \] For the lines to intersect, we require: \[ (\vec{a_2} - \vec{a_1}) \cdot (\vec{b_1} \times \vec{b_2}) = 0 \] This means that the vector \((\vec{a_2} - \vec{a_1})\) is perpendicular to the vector \((\vec{b_1} \times \vec{b_2})\). ### Step 3: Condition for Parallel Lines For the lines to be parallel, the direction vectors \(\vec{b_1}\) and \(\vec{b_2}\) must be proportional. This can be expressed as: \[ \vec{b_1} \times \vec{b_2} = \vec{0} \] This means that the direction vectors are either in the same direction or in opposite directions. ### Conclusion Thus, the lines will lie in a plane if either of the following conditions is satisfied: 1. \((\vec{a_2} - \vec{a_1}) \cdot (\vec{b_1} \times \vec{b_2}) = 0\) (they intersect). 2. \(\vec{b_1} \times \vec{b_2} = \vec{0}\) (they are parallel). ### Final Answer The lines will lie in a plane if either of the conditions mentioned above holds true.
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AAKASH INSTITUTE ENGLISH-THREE DIMENSIONAL GEOMETRY -ASSIGNMENT SECTION - A
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