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STATEMENT-1 : Let P(veca),Q(vecb) and R(...

STATEMENT-1 : Let `P(veca),Q(vecb)` and `R(vecc)` be three points such that `2veca+3vecb+5vecc=0`. Then the vector area of the `DeltaPQR` is a null vector.
And
STATEMENT-2 : Three collinear points from a triangle with zero area.

A

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-2

B

Statement-1 is True, Statement-2 is True, Statement-2 is not a correct explanation for Statement-2

C

Statement-1 is True, Statement-2 is False

D

Statement-1 is False, Statement-2 is True

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the statements provided and verify their correctness step by step. ### Given: - **Statement 1**: \(2\vec{a} + 3\vec{b} + 5\vec{c} = 0\). This implies a relationship between the vectors \(\vec{a}\), \(\vec{b}\), and \(\vec{c}\). - **Statement 2**: Three collinear points form a triangle with zero area. ### Step-by-Step Solution: 1. **Understanding the Equation**: \[ 2\vec{a} + 3\vec{b} + 5\vec{c} = 0 \] This equation can be rearranged to express one vector in terms of the others: \[ 5\vec{c} = -2\vec{a} - 3\vec{b} \] This indicates that \(\vec{c}\) can be expressed as a linear combination of \(\vec{a}\) and \(\vec{b}\). Therefore, the vectors \(\vec{a}\), \(\vec{b}\), and \(\vec{c}\) are collinear. **Hint**: Check if the vectors can be expressed as multiples of each other to confirm collinearity. 2. **Vector Area of Triangle**: The area of triangle \(PQR\) formed by points \(P(\vec{a})\), \(Q(\vec{b})\), and \(R(\vec{c})\) can be calculated using the formula for the area of a triangle formed by vectors: \[ \text{Area} = \frac{1}{2} |\vec{PQ} \times \vec{PR}| \] Where \(\vec{PQ} = \vec{b} - \vec{a}\) and \(\vec{PR} = \vec{c} - \vec{a}\). 3. **Collinearity Implication**: Since \(\vec{a}\), \(\vec{b}\), and \(\vec{c}\) are collinear, the vectors \(\vec{PQ}\) and \(\vec{PR}\) will also be collinear. The cross product of two collinear vectors is zero: \[ \vec{PQ} \times \vec{PR} = 0 \] Therefore, the area of triangle \(PQR\) is: \[ \text{Area} = \frac{1}{2} \cdot 0 = 0 \] **Hint**: Remember that the area of a triangle is zero if the points are collinear. 4. **Conclusion**: - **Statement 1** is true because the area of triangle \(PQR\) is indeed a null vector (zero area). - **Statement 2** is also true as it correctly states that three collinear points form a triangle with zero area. - Thus, Statement 2 provides a correct explanation for Statement 1. ### Final Answer: Both statements are correct, and Statement 2 is the correct explanation for Statement 1. **Correct Option**: A (Both statements are true, and Statement 2 explains Statement 1).
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