Home
Class 12
MATHS
STATEMENT-1 : The vector hati bisects th...

STATEMENT-1 : The vector `hati` bisects the angle between the vectors `hati-2hatj-2hatk` and `hati+2hatj+2hatk`.
And
STATEMENT-2 : The vector along the angle bisector of the vector `veca` and `vecb` is given by `+-((veca)/(|veca|)+-(vecb)/(|vecb|))` where `|veca|.|vecb|ne 0`

A

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-3

B

Statement-1 is True, Statement-2 is True, Statement-2 is not a correct explanation for Statement-3

C

Statement-1 is True, Statement-2 is False

D

Statement-1 is False, Statement-2 is True

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will analyze both statements step by step. ### Step 1: Analyze Statement 1 We need to check if the vector \(\hat{i}\) bisects the angle between the vectors \(\vec{a} = \hat{i} - 2\hat{j} - 2\hat{k}\) and \(\vec{b} = \hat{i} + 2\hat{j} + 2\hat{k}\). 1. **Find the direction of the vectors**: - \(\vec{a} = \hat{i} - 2\hat{j} - 2\hat{k}\) - \(\vec{b} = \hat{i} + 2\hat{j} + 2\hat{k}\) 2. **Calculate the magnitudes**: - \(|\vec{a}| = \sqrt{1^2 + (-2)^2 + (-2)^2} = \sqrt{1 + 4 + 4} = \sqrt{9} = 3\) - \(|\vec{b}| = \sqrt{1^2 + 2^2 + 2^2} = \sqrt{1 + 4 + 4} = \sqrt{9} = 3\) 3. **Normalize the vectors**: - \(\hat{a} = \frac{\vec{a}}{|\vec{a}|} = \frac{\hat{i} - 2\hat{j} - 2\hat{k}}{3} = \frac{1}{3}\hat{i} - \frac{2}{3}\hat{j} - \frac{2}{3}\hat{k}\) - \(\hat{b} = \frac{\vec{b}}{|\vec{b}|} = \frac{\hat{i} + 2\hat{j} + 2\hat{k}}{3} = \frac{1}{3}\hat{i} + \frac{2}{3}\hat{j} + \frac{2}{3}\hat{k}\) 4. **Find the angle bisector**: The angle bisector \(\hat{t}\) can be given by: \[ \hat{t} = \hat{a} + \hat{b} = \left(\frac{1}{3}\hat{i} - \frac{2}{3}\hat{j} - \frac{2}{3}\hat{k}\right) + \left(\frac{1}{3}\hat{i} + \frac{2}{3}\hat{j} + \frac{2}{3}\hat{k}\right) \] Simplifying this: \[ \hat{t} = \frac{2}{3}\hat{i} + 0\hat{j} + 0\hat{k} = \frac{2}{3}\hat{i} \] 5. **Check if \(\hat{i}\) is a scalar multiple of \(\hat{t}\)**: The vector \(\hat{i}\) is indeed a scalar multiple of \(\hat{t}\) since \(\hat{t} = \frac{2}{3}\hat{i}\). Thus, \(\hat{i}\) bisects the angle between \(\vec{a}\) and \(\vec{b}\). ### Conclusion for Statement 1: **Statement 1 is True.** --- ### Step 2: Analyze Statement 2 The statement claims that the vector along the angle bisector of vectors \(\vec{a}\) and \(\vec{b}\) is given by: \[ \pm\left(\frac{\vec{a}}{|\vec{a}|} + \frac{\vec{b}}{|\vec{b}|}\right) \] 1. **Substituting the normalized vectors**: From our previous calculations, we have: \[ \hat{a} + \hat{b} = \frac{2}{3}\hat{i} \] 2. **Check the given formula**: The formula states: \[ \hat{t} = \pm\left(\frac{\hat{i} - 2\hat{j} - 2\hat{k}}{3} + \frac{\hat{i} + 2\hat{j} + 2\hat{k}}{3}\right) \] Simplifying this gives: \[ \hat{t} = \pm\left(\frac{2}{3}\hat{i}\right) \] This matches our previous result, but the statement also implies that it holds for all cases where \(|\vec{a}| \cdot |\vec{b}| \neq 0\). ### Conclusion for Statement 2: **Statement 2 is True.** --- ### Final Conclusion: - **Statement 1 is True.** - **Statement 2 is True.**
Promotional Banner

Topper's Solved these Questions

  • VECTOR ALGEBRA

    AAKASH INSTITUTE ENGLISH|Exercise SECTION-F (Matrix-Match Type Questions)|3 Videos
  • VECTOR ALGEBRA

    AAKASH INSTITUTE ENGLISH|Exercise SECTION-G (Integer Answer Type Questions)|2 Videos
  • VECTOR ALGEBRA

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION-D) Comprehesion-II|3 Videos
  • TRIGNOMETRIC FUNCTIONS

    AAKASH INSTITUTE ENGLISH|Exercise Section - J (Akash Challengers Question)|16 Videos

Similar Questions

Explore conceptually related problems

The angle between the two vectors vecA=hati+2hatj-hatk and vecB=-hati+hatj-2hatk

Find the sine of the angle between the vectors veca=2hati-hatj+3hatk and vecb=hati+3hatj+2hatk .

Find the vector of magnitude 3, bisecting the angle between the vectors veca=2hati+hatj-hatk and vecb=hati-2hatj+hatk .

The angle between the two vectors vecA=2hati+3hatj+4hatk and vecB=1hati+2hatj-3hatk will be :

Find the angle 'theta' between the vector veca=2hati+3hatj-4hatk and vecb=3hati-2hatj+4hatk .

If the sides of an angle are given by vectors veca=hati-2hatj+2hatk and vecb=2hati+hatj+2hatk , then find the internal bisector of the angle.

Find the resultant of vectors veca=hati-hatj+2hatk and vecb=hati+2hatj-4hatk . Find the unit vector in the direction of the resultant vector.

Find the angle between the vectors veca = 6 hati + 2 hatj + 3 hatk, vecb = 2 hati - 9 hatj + 6 hatk

Find the scalar product of vectors veca=2hati-hatj+2hatk and vecb=hati-3hatj-5hatk

If veca=7hati-4hatj-4hatk and vecb=-2hati-hatj+2hatk , determine vector vecc along the internal bisector of the angle between vectors veca and vecb such that |vecc|= 5sqrt6 .