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Find the general solution of 2sin theta+...

Find the general solution of `2sin theta+1=0`

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We have,
`2sin theta+1=0`
`rArr sin theta=-1/2`
A value of `theta` satisfying this equation is `-pi/6`
`therefore sin theta=-1/2`
`rArr sin theta=sin(-pi/6)`
`rArr theta = npi +(-1)^(n)(-pi/6), n int Z`
`rArr theta=npi + (-1)^(n) (-pi/6), n int Z`
`rArr theta=npi +(-1)^(n+1) pi/6, n int Z`
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AAKASH INSTITUTE ENGLISH-TRIGNOMETRIC FUNCTIONS -Section - J (Akash Challengers Question)
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