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If A,B and C are the angle of a triangle...

If A,B and C are the angle of a triangle show that `|{:(sin2A,sinC,sinB),(sinC,sin2B,sinA),(sinB,sinA,sin2C):}|=0.`

A

`cotA = (sinB+sinC)/(cosC + sinB)`

B

`cotB=(sinA-sinC)/(cosC-cosA)`

C

`tanA=(sinA+sinC)/(cosC-cosB)`

D

`tanB = (sinB-sinC)/(cosC-cosB)`

Text Solution

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The correct Answer is:
B
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