Solve the equation `sin^(2)ntheta - sin^(2)(n-1)theta = sin^(2)theta`

Explanation

To solve the equation \( \sin^2(n\theta) - \sin^2((n-1)\theta) = \sin^2(\theta) \), we will follow these steps:

### Step 1: Use the identity for the difference of squares
We can use the identity:
\[ \sin^2 A - \sin^2 B = (\sin A + \sin B)(\sin A - \sin B) \]
Let \( A = n\theta \) and \( B = (n-1)\theta \). Thus, we rewrite the left-hand side:
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