Solve for x and y if `sqrt(sinx cosy)=0` and `2sin^(2)x - cos2y-2=0`

Explanation

To solve the equations \( \sqrt{\sin x \cos y} = 0 \) and \( 2\sin^2 x - \cos 2y - 2 = 0 \), we will follow these steps:

### Step 1: Solve the first equation
Starting with the first equation:
\[ \sqrt{\sin x \cos y} = 0 \]
Squaring both sides gives:
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