Let x in `[0,2pi]` The curve `y=secx tanx +2tanx - sec x` and the line y=2 intersect in

Options

A. No points
B. 2 points
C. 3 points
D. 4 points

Explanation

To find the points of intersection between the curve \( y = \sec x \tan x + 2 \tan x - \sec x \) and the line \( y = 2 \) within the interval \( [0, 2\pi] \), we will follow these steps:

### Step 1: Set the equations equal to each other
We start by setting the equation of the curve equal to the line:
\[ \sec x \tan x + 2 \tan x - \sec x = 2 \]

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