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A : If m and m(e) are moving mass, rest ...

A : If m and `m_(e)` are moving mass, rest mass of a body and c is velocity of light, then kinetic energy of the body is `E=(m-m_(0))c^(2)`
R : Total energy of a body is sum of kinetic energy and rest mass energy.

A

If both Assertion & Reason are true and the reason is the correct explanation of the assertion, then mark (1).

B

If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark (2).

C

If Assertion is true statement but Reason is false, then mark (3).

D

If both Assertion and Reason are false statements, then mark (4).

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze both the assertion (A) and the reason (R) provided. ### Step-by-Step Solution: 1. **Understanding the Assertion (A)**: - The assertion states that the kinetic energy (E) of a body is given by the formula \( E = (m - m_0)c^2 \), where: - \( m \) is the moving mass (relativistic mass). - \( m_0 \) is the rest mass of the body. - \( c \) is the speed of light. - This formula is derived from the concept of relativistic energy, where the total energy \( E \) of a body in motion is expressed as \( E = mc^2 \). 2. **Understanding the Reason (R)**: - The reason states that the total energy of a body is the sum of its kinetic energy and rest mass energy. - Mathematically, this can be expressed as: \[ E = K + m_0c^2 \] where \( K \) is the kinetic energy. 3. **Deriving the Kinetic Energy**: - From the total energy equation, we can rearrange it to find the kinetic energy: \[ K = E - m_0c^2 \] - Substituting \( E = mc^2 \) into this equation gives: \[ K = mc^2 - m_0c^2 \] - Factoring out \( c^2 \) from the right side: \[ K = (m - m_0)c^2 \] - This matches the assertion provided in (A). 4. **Conclusion**: - Both the assertion (A) and the reason (R) are true. - Furthermore, the reason (R) correctly explains the assertion (A). ### Final Answer: - Both A and R are true, and R is the correct explanation of A.
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