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A body performs S.H.M. Its kinetic energ...

A body performs S.H.M. Its kinetic energy K varies with time t as indicated by graph

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To solve the problem regarding the variation of kinetic energy (K) of a body performing simple harmonic motion (SHM) with time (t), we can follow these steps: ### Step 1: Understand the Kinetic Energy Formula The kinetic energy (K) of a body is given by the formula: \[ K = \frac{1}{2} mv^2 \] where \( m \) is the mass of the body and \( v \) is its velocity. ### Step 2: Write the Velocity Equation for SHM In simple harmonic motion, the velocity \( v \) can be expressed as: \[ v = A \omega \cos(\omega t + \alpha) \] where: - \( A \) is the amplitude, - \( \omega \) is the angular frequency, - \( \alpha \) is the phase constant. ### Step 3: Substitute Velocity into the Kinetic Energy Formula Now, substitute the expression for velocity into the kinetic energy formula: \[ K = \frac{1}{2} m (A \omega \cos(\omega t + \alpha))^2 \] This simplifies to: \[ K = \frac{1}{2} m A^2 \omega^2 \cos^2(\omega t + \alpha) \] ### Step 4: Analyze the Kinetic Energy Expression From the expression \( K = \frac{1}{2} m A^2 \omega^2 \cos^2(\omega t + \alpha) \), we can observe: - The term \( \cos^2(\omega t + \alpha) \) is always non-negative (i.e., it is always greater than or equal to zero). - Therefore, the kinetic energy \( K \) will always be a positive quantity or zero. ### Step 5: Determine the Graph of Kinetic Energy Since \( K \) varies with \( \cos^2(\omega t + \alpha) \), the graph of kinetic energy versus time will resemble the graph of \( \cos^2 \) function, which oscillates between 0 and a maximum value (when \( \cos^2 \) is 1). ### Step 6: Choose the Correct Option From the options provided, we need to identify the graph that represents the positive oscillation of kinetic energy, which is consistent with the behavior of \( \cos^2 \) function. The correct option will be the one that shows a graph oscillating between 0 and a maximum positive value. ### Final Conclusion Thus, based on the analysis, the correct option is the one that represents the kinetic energy graph as a function of time that is always non-negative. ---
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AAKASH INSTITUTE ENGLISH-OSCILLATIONS-Assignment (Section - B) (OBJECTIVE TYPE QUESTIONS)
  1. A particle execute SHM and its position varies with time as x = A sin ...

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  2. A particle of mass m in a unidirectional potential field have potentia...

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  3. A particle is executing SHM and its velocity v is related to its posit...

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  4. A loaded vertical spring executes simple harmonic oscillations with pe...

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  5. A body performs S.H.M. Its kinetic energy K varies with time t as ind...

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  6. A particle is performing SHM energy of vibration 90J and amplitude 6cm...

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  7. The variations of potential energy (U) with position x for three simpl...

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  8. If the particle repeats its motion after a fixed time interval of 8 s ...

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  9. A particle is executing SHM with total mechanical energy 90J and ampli...

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  10. A linear harmonic oscillator of force constant 6 xx 10^(5) N/m and amp...

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  11. A seconds pendulum is mounted in a rocket. Its period of oscillation d...

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  12. The curve between square of frequency of oscillation and length of the...

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  13. A simple pendulum of mass m executes SHM with total energy E. if at an...

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  14. There is a rod of length l and mass m. It is hinged at one end to the ...

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  15. A rectangular block of mass m and area of cross-section A floats in a ...

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  16. When a mass of 5 kg is suspended from a spring of negligible mass and ...

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  17. In the figure shown, there is friction between the blocks P and Q but ...

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  18. A flat horizontal board moves up and down under SHM vertically with am...

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  19. A simple pendulum with iron bob has a time period T. The bob is now im...

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  20. When a mass m attached to a spring it oscillates with period 4s. When ...

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