Two ideal diodes are connected to a battery as shown in the circuit. The current supplied by the battery is

Options

A. `0.25 A`
B. `0.5 A`
C. 0.75 A`
D. Zero

Answer

To solve the problem of finding the current supplied by the battery in the given circuit with two ideal diodes, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Circuit Configuration**:
- We have a voltage source of 5 volts connected to two resistors (20 ohms and 10 ohms) in parallel, along with two diodes (D1 and D2).

2. **Determine the State of the Diodes**:
- D1 is in forward bias because the voltage at its anode is greater than at its cathode.
- D2 is in reverse bias because the voltage at its anode is less than at its cathode.
- Since D2 is reverse-biased, it will not conduct any current.

3. **Calculate the Equivalent Resistance**:
- Since D2 does not conduct, we only consider D1 and the 10-ohm resistor.
- The 20-ohm resistor is not in the circuit because D2 is reverse-biased, so we only need to consider the 10-ohm resistor.

4. **Apply Ohm's Law**:
- The current (I) supplied by the battery can be calculated using Ohm's Law, which states \( I = \frac{V}{R} \).
- Here, \( V = 5 \) volts and \( R = 10 \) ohms.
- Therefore, \( I = \frac{5}{10} = 0.5 \) amps.

5. **Conclusion**:
- The current supplied by the battery is 0.5 amps.

### Final Answer:
The current supplied by the battery is **0.5 amps**.

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