How much copper is deposited on the cathode if a current of 3A is passed through aqueous `CuSO_(4)` solution for 15 minutes?

Explanation

To determine how much copper is deposited on the cathode when a current of 3 A is passed through an aqueous CuSO₄ solution for 15 minutes, we can use Faraday's first law of electrolysis. Here’s a step-by-step solution:

### Step 1: Convert Time to Seconds
First, we need to convert the time from minutes to seconds because the current is given in amperes (A), which is coulombs per second (C/s).

\[ \text{Time} = 15 \text{ minutes} \times 60 \text{ seconds/minute} = 900 \text{ seconds} \]
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