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What is the amount of O(2) liberated at ...

What is the amount of `O_(2)` liberated at STP by ''30 volume'' 1 L solution of `H_(2)O_(2)`?

A

1.5 L

B

2.5 L

C

30 L

D

3 L

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question of how much oxygen gas (`O2`) is liberated at STP by a "30 volume" 1 L solution of `H2O2`, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Volume Strength**: - The term "30 volume" means that 1 liter of the solution of hydrogen peroxide (`H2O2`) can liberate 30 liters of oxygen gas (`O2`) at standard temperature and pressure (STP). 2. **Using the Definition**: - According to the definition of volume strength, if the volume strength is 30 V, it indicates that 1 liter of the `H2O2` solution will produce 30 liters of `O2` gas. 3. **Calculating the Amount of `O2`**: - Since we have 1 liter of a 30 volume solution of `H2O2`, it will liberate exactly 30 liters of oxygen gas. 4. **Conclusion**: - Therefore, the amount of `O2` liberated at STP by 1 liter of 30 volume `H2O2` solution is **30 liters**. ### Final Answer: The amount of `O2` liberated at STP by 1 liter of 30 volume `H2O2` is **30 liters**.
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