The incorrect match is

Options

A.
B.
C.
D.

Answer

To determine the incorrect match regarding the aromaticity of the given compounds, we will analyze each option based on the rules of aromaticity and anti-aromaticity.

### Step-by-Step Solution:

1. **Understand the Rules of Aromaticity:**
- A compound is aromatic if it satisfies the following criteria:
- It is cyclic.
- It is planar.
- It has a conjugated π electron system.
- It follows Huckel's rule: the number of π electrons (denoted as \( n \)) must be of the form \( 4n + 2 \) (where \( n \) is a non-negative integer, e.g., 2, 6, 10, etc.).
- A compound is anti-aromatic if it has \( 4n \) π electrons (e.g., 4, 8, 12, etc.).
- If a compound does not meet the criteria for aromatic or anti-aromatic, it is classified as non-aromatic.

2. **Evaluate Each Option:**
- **Option A:** Count the π electrons. If it has 4 π electrons, it is anti-aromatic. This option is correctly matched.
- **Option B:** Analyze the structure. If it has 6 π electrons (2 from double bonds and 4 from other sources), it is aromatic. The presence of a vacant orbital in boron allows it to participate in resonance, stabilizing the compound. Thus, this option is incorrectly matched as aromatic instead of anti-aromatic.
- **Option C:** If there are no π electrons, it is non-aromatic. This option is correctly matched.
- **Option D:** If there are 6 π electrons (including a negative charge representing 2 electrons), it is aromatic. This option is correctly matched.

3. **Identify the Incorrect Match:**
- After evaluating all options, we find that **Option B** is incorrectly matched as it should be classified as aromatic due to the presence of 6 π electrons.

### Final Answer:
The incorrect match is **Option B**.