The reaction of `CH_(3)CH=CH_(2)` with HOCl will yield

Options

A. 2-chloro-1-propanol
B. 3-chloro-2-propanol
C. 1-chloro-2-propanol
D. 1-chloro-1-propanol

Answer

To solve the question regarding the reaction of propene (CH₃CH=CH₂) with HOCl, we can follow these steps:

### Step 1: Identify the Reactants
The reactant is propene, which has the structure CH₃CH=CH₂. The other reactant is HOCl, which consists of a hydroxyl group (OH) and a chlorine atom (Cl).

### Step 2: Understand the Electrophilic Addition Mechanism
In the reaction, the double bond in propene acts as a nucleophile and attacks the electrophilic part of HOCl. The oxygen in HOCl is more electronegative, resulting in a partial positive charge on the chlorine atom (Cl) and a partial negative charge on the oxygen (O).

### Step 3: Formation of a Carbocation
When the double bond attacks the chlorine, a carbocation is formed. In this case, the more stable secondary carbocation is formed at the second carbon (C2) of propene:
- CH₃CH⁺CH₂Cl

### Step 4: Nucleophilic Attack by Hydroxide Ion
The hydroxide ion (OH⁻) from HOCl will then attack the carbocation. This results in the formation of a compound where the OH group is attached to the second carbon:
- CH₃CHOHCH₂Cl

### Step 5: Naming the Product
Now, we need to name the product. The compound has:
- A chlorine atom (Cl) on the first carbon (C1)
- A hydroxyl group (OH) on the second carbon (C2)

Thus, the IUPAC name of the compound is 1-chloro-2-propanol, which can also be referred to as 1-chloro-2-propanol.

### Conclusion
The final product of the reaction of propene (CH₃CH=CH₂) with HOCl is 1-chloro-2-propanol.

### Answer
The correct option is **1-chloro-2-propanol**.

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