Toulene `overset(K_(2)Cr_(2)O_(7))underset(H_(2)SO_(4))to` Y. Here Y is

Options

A. Benzaldehyde
B. Toulene
C. Benzoic acid
D. Ethylbenzene

Answer

To solve the question regarding the oxidation of toluene with potassium dichromate (K₂Cr₂O₇) in the presence of sulfuric acid (H₂SO₄), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant is toluene, which has the chemical formula C₇H₈ (C₆H₅-CH₃).

2. **Understand the Reaction Conditions**:
- The reaction is carried out using K₂Cr₂O₇, a strong oxidizing agent, in the presence of H₂SO₄, which acts as an acid catalyst.

3. **Determine the Type of Reaction**:
- Toluene contains a methyl group (-CH₃) attached to the benzene ring. Under strong oxidation conditions, the methyl group can be oxidized to a carboxylic acid.

4. **Predict the Product**:
- The methyl group in toluene will be oxidized to a carboxylic acid, specifically benzoic acid (C₆H₅COOH).
- The oxidation process can be summarized as follows:
- Toluene (C₆H₅-CH₃) → Benzoic acid (C₆H₅COOH)

5. **Write the Balanced Reaction**:
- The overall reaction can be represented as:
\[ C₆H₅-CH₃ + [O] \rightarrow C₆H₅-COOH \]
- Here, [O] represents the oxygen supplied by the oxidizing agent K₂Cr₂O₇.

6. **Final Product**:
- The final product Y is benzoic acid (C₆H₅COOH).

### Conclusion:
The product Y formed from the oxidation of toluene using K₂Cr₂O₇ in the presence of H₂SO₄ is **benzoic acid**.