In kharash effect,reaction follows

Options

A. Free radical substituion
B. Electrohilic addition
C. Free radical addition
D. Nucleophillic addition

Answer

To solve the question regarding the Kharash effect and the mechanism it follows, we can break it down into a step-by-step explanation.

### Step-by-Step Solution:

1. **Understanding the Kharash Effect**:
- The Kharash effect refers to the addition of HBr to alkenes in the presence of peroxides, which leads to the formation of products that follow the anti-Markovnikov rule. This means that the bromine atom attaches to the less substituted carbon atom of the alkene.

2. **Identifying the Reaction**:
- The reaction involves an alkene, specifically propene (CH3-CH=CH2), and HBr in the presence of a peroxide (like benzoyl peroxide).

3. **Mechanism Initiation**:
- The reaction begins with the homolytic cleavage of the peroxide bond in benzoyl peroxide (C6H5-C(=O)-O-O-C(=O)-C6H5). This cleavage generates two benzoyloxy radicals (C6H5-COO•).

4. **Formation of Free Radicals**:
- The benzoyloxy radicals decompose to form phenyl radicals (C6H5•) and carbon dioxide (CO2). The phenyl radical is a key initiator in this reaction.

5. **Reaction of Phenyl Radical with HBr**:
- The phenyl radical (C6H5•) reacts with HBr to generate bromobenzene (C6H5Br) and a bromine radical (Br•).

6. **Alkene Reaction with Bromine Radical**:
- The bromine radical (Br•) then reacts with the alkene (CH3-CH=CH2). This can lead to two possible products:
- One product has the bromine atom added to the less substituted carbon (CH3-CH2-CH2Br).
- The other product has the bromine atom added to the more substituted carbon (CH3-CHBr-CH3).

7. **Stability of Free Radicals**:
- The product where the bromine is added to the less substituted carbon (resulting in a secondary free radical) is more stable than the product where bromine is added to the more substituted carbon (resulting in a primary free radical).

8. **Final Product Formation**:
- The stable secondary free radical then reacts with HBr again, leading to the final product, which is 1-bromopropane (CH3-CH2-CH2Br).

### Conclusion:
The Kharash effect follows a free radical addition mechanism, resulting in the formation of products according to the anti-Markovnikov rule.

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